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PHP+JS三级菜单联动菜单实现方法

2020-02-21 20:43:26
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本文实例讲述了PHP+JS三级菜单联动菜单实现方法。分享给大家供大家参考,具体如下:

<html>  <head>    <title>      智能递归菜单-读取数据库    </title>    <style>      TD { FONT-FAMILY: "Verdana", "宋体"; FONT-SIZE: 12px; LINE-HEIGHT: 130%;      letter-spacing:1px } A:link { COLOR: #990000; FONT-FAMILY: "Verdana", "宋体";      FONT-SIZE: 12px; TEXT-DECORATION: none; letter-spacing:1px } A:visited      { COLOR: #990000; FONT-FAMILY: "Verdana", "宋体"; FONT-SIZE: 12px; TEXT-DECORATION:      none; letter-spacing:1px } A:active { COLOR: #990000; FONT-FAMILY: "Verdana",      "宋体"; FONT-SIZE: 12px; TEXT-DECORATION: none; letter-spacing:1px } A:hover      { COLOR: #ff0000; FONT-FAMILY: "Verdana", "宋体"; FONT-SIZE: 12px; TEXT-DECORATION:      underline; letter-spacing:1px } .Menu { COLOR:#000000; FONT-FAMILY: "Verdana",      "宋体"; FONT-SIZE: 12px; CURSOR: hand }    </style>    <script language=javascript>      function ShowMenu(MenuID) {        if (MenuID.style.display == "none") {          MenuID.style.display = "";        } else {          MenuID.style.display = "none";        }      }    </script>  </head>  <body><?php// $Id:$//基本变量设置$GLOBALS["ID"] = 1;//用来跟踪下拉菜单的ID号 $layer=1;//用来跟踪当前菜单的级数//连接数据库$Con=mysql_connect( "localhost", "root", "123456"); mysql_select_db("menu");//提取一级菜单$sql="select * from menu where parent_id=0" ;$result=mysql_query($sql,$Con);//如果一级菜单存在则开始菜单的显示if(mysql_num_rows($result)>0) ShowTreeMenu($Con, $result, $layer, $ID); //=============================================//显示树型菜单函数 ShowTreeMenu($con,$result,$layer) //$con:数据库连接 //$result:需要显示的菜单记录集//layer:需要显示的菜单的级数 //=============================================functionShowTreeMenu($Con, $result, $layer) {//取得需要显示的菜单的项目数$numrows=mysql_num_rows($result);  //开始显示菜单,每个子菜单都用一个表格来表示 echo "   < tablecellpadding = '0'cellspacing = '0'border = '0' > "; for($rows=0;$rows        <$numrows;$rows++) { //将当前菜单项目的内容导入数组 $menu=mysql_fetch_array($result);        //提取菜单项目的子菜单记录集 $sql="select * frommenuwhereparent_id = $menu[id]" ; $result_sub=mysql_query($sql,$Con);        echo " < tr > "; //如果该菜单项目有子菜单,则添加JavaScript onClick语句 if(mysql_num_rows($result_sub)>          0) { echo " < tdwidth = '20' > < imgsrc = 'tree_expand.gif'border = '0' > < / td > "; echo " < tdclass = 'Menu'onClick = 'javascript:ShowMenu(Menu".$GLOBALS["ID"].");' > "; } else { echo " < tdwidth = '20' > < imgsrc = 'tree_collapse.gif'border = '0' > < / td > "; echo " < tdclass = 'Menu' > "; } //如果该菜单项目没有子菜单,并指定了超级连接地址,则指定为超级连接, //否则只显示菜单名称 if($menu[url]!="")              echo " < ahref = '$menu[url]' > $menu[name] < / a > "; else echo $menu[name]; echo " < / td > < / tr > "; //如果该菜单项目有子菜单,则显示子菜单 if(mysql_num_rows($result_sub)>0) { //指定该子菜单的ID和style,以便和onClick语句相对应            echo " < trid = Menu".$GLOBALS["ID "]++ . " style='display:none'>";  echo "<td width='20'></td>";  echo "<td>";  //将级数加1  $layer++;  //递归调用ShowTreeMenu()函数,生成子菜单   ShowTreeMenu($Con,$result_sub,$layer);  //子菜单处理完成,返回到递归的上一层,将级数减1  $layer--;  echo "< / td > < / tr > ";  }  //继续显示下一个菜单项目  } echo " < / table > "; }  ?>      <?php      $id=1 ;      function test() {      global $id; unset($id);      }      test();      echo " < fontclass = menu > ".($id). " < / font > ";      // 在 PHP 4 中这里会打印出 1      ?>      <?php      $a=1 ;      $b=2 ;      function Sum() {      global $a, $b; $b=$ a + $b;      }      Sum();      echo " < fontclass = menu > ".$b. " < / font > ";      ?>  </body></html>            
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